SOLUTION: Solve for x
Log2(10x)=log2(3x+14)
2log3^x=log3^4
Log5(4x-3)=log5(x+1)
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Question 1028244: Solve for x
Log2(10x)=log2(3x+14)
2log3^x=log3^4
Log5(4x-3)=log5(x+1)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve for x
Log2(10x)=log2(3x+14)
If they're base 2:
10x = 3x + 14
7x = 14
x = 2
=========================
2log3^x=log3^4
Not clear.
===================
Log5(4x-3)=log5(x+1)
Similar to the 1st one.
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