SOLUTION: We were asked to solve logarithmic inequations, and although I could solve it, I stopped at a dead end, in which I couldn't find a ''good'' answer..
i) 2*ln(x+2)-1 > 0
ii) log(
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Question 1028184: We were asked to solve logarithmic inequations, and although I could solve it, I stopped at a dead end, in which I couldn't find a ''good'' answer..
i) 2*ln(x+2)-1 > 0
ii) log(3-2x) > 1 + log(x+5)
*Sorry if I posted this again*
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
i)
==>
==>
==> ≈ -0.35.
ii)
==>
==>
==>
==>
==>
The critical numbers are -47/12 and -5. (The numbers that make the numerator and denominator equal to zero.)
Choose test numbers -6, -4, and 0. (Corresponding to the partition (,-5), (-5,-47/12), (-47/12, ). )
Upon substitution into , the signs are (-), (+), and (-).
Therefore the solution is the open interval (-5,-47/12).
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