SOLUTION: The excersise goes like that: ''Solve this logarithmix equation: 1. 2*log*(2x-1) - log*(3x-2x^2) = log*(4x-3)-log*x Thank you for replying!

SOLUTION: The excersise goes like that: ''Solve this logarithmix equation: 1. 2log(2x-1) - log(3x-2x^2) = log(4x-3)-log*x Thank you for replying!

Question 1028182: The excersise goes like that:
''Solve this logarithmix equation:
1. 2*log*(2x-1) - log*(3x-2x^2) = log*(4x-3)-log*x
Thank you for replying!
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

Temporary change in variables saying as .

You are not interested in x=0, because you cannot have log of negative values as would happen in the original equation. Put attention instead on the remaining roots of the quadratic factor.

Discrim,
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