SOLUTION: how would you do 3log6X= log6 2+ log 6 32
all of the sixes are suppose to be the small number
the answer is suppose to be 4 but I dont know how it would be done. Could you show
Algebra.Com
Question 1021322: how would you do 3log6X= log6 2+ log 6 32
all of the sixes are suppose to be the small number
the answer is suppose to be 4 but I dont know how it would be done. Could you show me the steps?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
3*log(6,x)=log(6,2)+log(6,32)
Inside the rendering tags, .
Exponents the same 3 for both bases, so .
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!
how would you do 3log6X= log6 2+ log 6 32
all of the sixes are suppose to be the small number
the answer is suppose to be 4 but I dont know how it would be done. Could you show me the steps?
, or
RELATED QUESTIONS
Evaluate the expression log5 (log2 32)
the 5 and 2 are suppose to be small and towards... (answered by josgarithmetic,math_helper,ikleyn)
what is the exponential form of log(9)1/81=-2 Note the number in the parenthesis is... (answered by jim_thompson5910)
Logx49=2 in exponential form...the x is suppose to be small
Solve for the unknown... (answered by scott8148)
I am suppose to reduce
15x^3/6x^-3
Would the answer be 5x^6/2... (answered by edjones,Maths68)
evaluate log(9)27-long(27)9 The numbers in the parenthesis are suppose to be small... (answered by MathTherapy)
This is for a 4th grader.......we are suppose to add these numbers together to get the... (answered by ptaylor)
solve (3^2x) -[5(3^x)]=-6
I've tried a few different roots..nothing seems to be... (answered by Alan3354)
express log9(2)9 + 2log(2)5 - log(2)3 as a single logarithm. Note that the numbers in the (answered by ankor@dixie-net.com)
How do you expand the expression log7x^2y. the 2 suppose to be a... (answered by Alan3354)