SOLUTION: Solve the logarithm and check.
1). 3^5x=27^2x+1
2). 5^5x-6=50
Thanks show work please.
Algebra.Com
Question 1020036: Solve the logarithm and check.
1). 3^5x=27^2x+1
2). 5^5x-6=50
Thanks show work please.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
These are exponential equations, not logarithms.
John

My calculator said it, I believe it, that settles it
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