SOLUTION: Solve the equation algebraically: log (base 1.2) x = 1-log (base 1.2) (x-0.2)
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Question 1019747: Solve the equation algebraically: log (base 1.2) x = 1-log (base 1.2) (x-0.2)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
logs base 1.2
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log(x) = 1-log(x-0.2)
log(x) = log(1.2) - log(x-0.2)
log(x) + log(x-0.2) = log(1.2)
log(x*(x-0.2)) = log(1.2)
Since logs have the same base:
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x*(x-0.2) = 1.2
Solve the quadratic.
Check the solutions to avoid logs of negatives.
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