SOLUTION: How do you solve indicial equations like this, other than by graphing (which shows two solutions) although this does not appear to be a quadratic? 2^x-3^(x-1)=1

Question 1011667: How do you solve indicial equations like this, other than by graphing (which shows two solutions) although this does not appear to be a quadratic?
2^x-3^(x-1)=1
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
.
How do you solve indicial equations like this, other than by graphing (which shows two solutions) although this does not appear to be a quadratic?
2^x-3^(x-1)=1
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One root is x = 1.

The other is x = 2.

There are no more roots.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do you solve indicial equations like this, other than by graphing (which shows two solutions) although this does not appear to be a quadratic?
2^x-3^(x-1)=1
------------------
You can use iterative methods like Newton's method or Newton-Raphson.
You can use Excel, which is the same as a calculator but more convenient.

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