SOLUTION: Please help me solve for x and y in this log problem:
log9(5)=logx/logy
Thank you!
Algebra.Com
Question 1006823: Please help me solve for x and y in this log problem:
log9(5)=logx/logy
Thank you!
Found 2 solutions by richard1234, jim_thompson5910:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
By change-of-base formula,
So (x,y) = (5,9) works.
But since
, we have that
for any k also works.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Change of base rule
Use the change of base rule to get
So x = 5 and y = 9
RELATED QUESTIONS
How do I approach, and solve, this problem?:
2^logX + 3^logY = 2^log(X+1) + 3^log(Y+1)
(answered by arunpaul)
solve for (x) and y log9(x)+logy(8)=2
(answered by Alan3354)
If x^2+y^2=7xy.prove that log(x+y/3)=1/2(logx+logy). Please help me
(answered by MathLover1)
Solve the following system for (x,y):
1. log9(x)+ logy(8)= 2
2. logx(9)+ log8(y)=... (answered by KMST)
Solve for x and y if
logx + logy = 4
logx + 2logy = 3
Note
Bases are in base 10
(answered by josgarithmetic)
Express y as a function of x. What is the domain?
a) log3+log y = log(x+2) - logx... (answered by josgarithmetic)
please help me solve this: log(x+10) - logx =... (answered by nerdybill)
Please help me solve... (answered by lwsshak3)
My question was log of sqrt (x (sqrt (2y (sqrt (z))))
What I did was (1/2)logx sqrt... (answered by Alan3354)