SOLUTION: Let ln (a)=2, ln (b)=3, ln (c)=5. Solve: f (x)=(ln (c^2))(ln (a^4/b^2))^-1

Question 1006514: Let ln (a)=2, ln (b)=3, ln (c)=5. Solve:
f (x)=(ln (c^2))(ln (a^4/b^2))^-1
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Let , , .
Solve:

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Let ln (a)=2, ln (b)=3, ln (c)=5. Solve:
f (x)=(ln (c^2))(ln (a^4/b^2))^-1

ln a = 2
ln b = 3
ln c = 5

------- Applying

We therefore have:

--- Applying = ln p � ln q
---- Applying = q ln p
----------- Substituting 5 for ln c, 2 for ln a, and 3 for ln b

, or
RELATED QUESTIONS
Solve for x: e^2x + 4e^-2x = 4. X= a. (1/2) ln 2 b. (1/3) ln 2 c. (1/3) ln 3 d.... (answered by stanbon,venugopalramana)
If ln a = 2, ln b = 3, and ln c = 5, evaluate the following: (a) \ln (\frac{a^{-4}... (answered by Alan3354)
Condense the following logatithmic expression: ln 10 + ln a + 2 ln b + 3 ln... (answered by lwsshak3)
Write as a single logarithm and check with a calculator a) ln 5 + ln 3 b) ln 2+ ln 10... (answered by jim_thompson5910,stanbon)
The exact solution for 12^sqrt of x =35 a. x= ln(35)/ln(12)^2 b. x= ln(12)/ln(35)^2... (answered by solver91311)
Please Help I have tried this problem and still getting the wrong answers. Thanks.... (answered by stanbon)
Solve the exponential equation. Express the solution set in terms of natural logarithms. (answered by LinnW)
how to solve with steps ln a - ln b + 2 ln c (answered by stanbon,Alan3354)
x= ln 3 + ln 4 - ln... (answered by jim_thompson5910)