SOLUTION: 2 times 3^2x-3 = 5^1-2x Please help me !!!

Question 1004903: 2 times 3^2x-3 = 5^1-2x
Please help me !!!
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
We will apply logarithms to this...

Taking the log of both sides, we get
log 2 + (2x-3)log 3 = (1-2x)log 5
Now multiply things out and collect like terms and get
log 2 + 2xlog 3 - 3log 3 = log 5 - 2xlog5
2xlog 3 + 2xlog 5 = log 5 + 3log 3 - log 2
2x(log 3 + log 5) = log 5 + 3log 3 - log 2
Now solve for x and get
x = (log 5 + 3log 3 - log 2) / 2(log 3 + log 5)
You can get the numerical value on a calculator...
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