SOLUTION: The function f(x) = 300(0.5) x/60 models the amount in pounds of a particular radioactive material stored in a concrete vault, where x is the number of years since the material was

Question 1004003: The function f(x) = 300(0.5) x/60 models the amount in pounds of a particular radioactive material stored in a concrete vault, where x is the number of years since the material was put into the vault. Find the amount of radioactive material in the vault after 170 years. Round to the nearest whole number.
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Hmmmm.... Are you sure it's 300*(0.5)*x/60? Look at it carefully. Anyway, I think your answer is 1,591,695.87 but what do I know.
RELATED QUESTIONS
The function f(x) = 300(0.5) x/100 models the amount in pounds of a particular... (answered by ikleyn)

The function f(x) = 300(0.5) x/60 models the amount in pounds of a particular radioactive (answered by fractalier)

The function f(x) = 800(.5)^ x/60 models the account in pounds of a particular... (answered by Boreal)

The function f(x) = 300(0.5) x/60 models the amount in pounds of a particular radioactive (answered by fractalier)

The function f(x)=900(0.5)^x/100 models the amount in pounds of a particular radioactive... (answered by josmiceli)

The function A = A0e^(-0.0099x) models the amount in pounds of a particular radioactive... (answered by josgarithmetic)

The function 900e^-0.0099^x models the amount in pounds of a particular radioactive... (answered by stanbon)

The function A=A0e^-0.01386x models the amount in pounds of a particular radioactive... (answered by stanbon)

The function A = A^ down 0e^-0.01386x�models the amount in pounds of a particular... (answered by ikleyn)