SOLUTION: What is the exact solution of the equation log4 = 1+log(x+1)

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Question 1002254: What is the exact solution of the equation
log4 = 1+log(x+1)
Found 3 solutions by dkppathak, Alan3354, MathTherapy:
Answer by dkppathak(439)   (Show Source): You can put this solution on YOUR website!
What is the exact solution of the equation
log4 = 1+log(x+1)
solution
we know log10=1 substitute 1= log10
log4 = 1+log(x+1)
log4= log10 +log(x+1) by using law log m +logn =log (mn)
log 4= log[10(x+1)] by anti log
4=10(x+1)
4/10 = x+1
0.4 =x+1
x=0.4-1=-0.6
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
What is the exact solution of the equation
log4 = 1+log(x+1)
-----
log4 - 1 = log(x+1)
log(4) - log(10) = log(x+1)
log(4/10) = log(x+1)
x+1 = 0.4
x = -0.6
Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!
What is the exact solution of the equation
log4 = 1+log(x+1)








10(x + 1) = 4 ------- Cross-multiplying

10x + 10 = 4

10x = - 6

x = , or  

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