SOLUTION: Solve LOGa(7x+1)=LOGa(4x+16)

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Question 100110: Solve LOGa(7x+1)=LOGa(4x+16)
Found 2 solutions by stanbon, bimanewton:
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
Solve LOGa(7x+1)=LOGa(4x+16)
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Since the logs are the same the anti-logs must be equal:
7x+1 = 4x+16
3x = 15
x = 5
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Cheers,
stan H.

Answer by bimanewton(8) About Me  (Show Source):
You can put this solution on YOUR website!
you can write
a%287x%2B1%29=a%284x%2B16%29
after that
%287x%2B1%29=%284x%2B16%29
3x=15
x=15%2F3
so x=5