SOLUTION: Solve LOGa(7x+1)=LOGa(4x+16)

Question 100110: Solve LOGa(7x+1)=LOGa(4x+16)
Found 2 solutions by stanbon, bimanewton:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve LOGa(7x+1)=LOGa(4x+16)
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Since the logs are the same the anti-logs must be equal:
7x+1 = 4x+16
3x = 15
x = 5
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Cheers,
stan H.
Answer by bimanewton(8) (Show Source): You can put this solution on YOUR website!
you can write

after that

so
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