SOLUTION: (lnx)^2-x+2=0

Question 1000441: (lnx)^2-x+2=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(lnx)^2-x+2=0
-----
Note: I have my doubts that you posted this problem correctly.
------------------
(ln(x))^2 = x-2
---
ln(x) = sqrt[x-2)
------
x = e^(sqrt(x-2)
RELATED QUESTIONS
(lnx)^2=lnx (answered by Alan3354)

lnx-3/lnx=-2 (answered by ikleyn,greenestamps)

lnx+ln(x+2)=4 (answered by bucky)

lnx+ln(x+2)=4 (answered by Edwin McCravy)

ln(20-x)=lnx^2 (answered by stanbon)

ln(x-2)+ln3=lnx (answered by stanbon)

ln(x+2)+lnx=ln(x+12) (answered by fractalier)

solve... (answered by edjones)

lnx=ln(2x-1)-ln(x-2) (answered by user_dude2008,nerdybill)