SOLUTION: Using laws of logarithms, write the expression below as a single logarithm 6 log(25-x^2) - (log(5+x)+log(5-x)) = log( Thanks!!

Algebra.Com
Question 1000415: Using laws of logarithms, write the expression below as a single logarithm
6 log(25-x^2) - (log(5+x)+log(5-x)) = log(
Thanks!!

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Using laws of logarithms, write the expression below as a single logarithm
6 log(25-x^2) - (log(5+x)+log(5-x))
-------
= log[(25-x^2)^6)/[log(5^2-x^2)]
-----
= log[25-x^2]^5
-----
= 5log(25-x^2)
---------
Cheers,
Stan H.
------------

RELATED QUESTIONS

Using laws of logarithms, write the expression below as a single logarithm 6 log(25-x^2) (answered by MathLover1)
Using laws of logarithms, write the expression below as a single logarithm.... (answered by fractalier)
Using laws of logarithms, write the expression below as a single logarithm.... (answered by MathLover1)
Using laws of logarithms, write the expression below as a single logarithm. 1/3 log 125... (answered by ikleyn)
Use properties of logarithms to condense the logarithmic expression. Write the expression (answered by josmiceli)
Use the laws of logarithms to rewrite each expression as a single logarithm, do NOT... (answered by lwsshak3,Alan3354)
write 2 log 2 + 3 log x - .5[log(x+3) + log(x-2)] as a single... (answered by tommyt3rd)
write as the positive logarithm of a single logarithm log 5 (x^2-1) - log 5... (answered by LinnW)
write as the positive logarithm of a single logarithm log 5 (x^2-1) - log 5... (answered by tommyt3rd)