# SOLUTION: #32) The lengths of the sides of three squares are s, s+1, s+2. If their total area is 365cm^2, find their total perimeter.

Algebra ->  Algebra  -> Formulas -> SOLUTION: #32) The lengths of the sides of three squares are s, s+1, s+2. If their total area is 365cm^2, find their total perimeter.      Log On

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 Question 95703This question is from textbook Geometry : #32) The lengths of the sides of three squares are s, s+1, s+2. If their total area is 365cm^2, find their total perimeter.This question is from textbook Geometry Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!S^2+(S+1)^2+(S+2)^2=365 S^2+S^2+2S+1+S^2+4S+4=365 3S^2+6S+5-365=0 3S^2+6S-360=0 3(S^2+2S-120=0 (S-10)(S+12)=0 S-10=0 S=10 FOR THE SIDE OF THE SMALLER SQUARE S=11 & S=12 FOR THE OTHER 2 SQUARES PERIMETERS=4*10+4*11+4*12=40+44+48=132CM.