SOLUTION: How many gallons of distilled water must be mixed with
50 gallons of 30% alcohol solution to obtain a 25% solution?
Algebra.Com
Question 931851: How many gallons of distilled water must be mixed with
50 gallons of 30% alcohol solution to obtain a 25% solution?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = gallons of 30% alcohol/water = 70% water/alcohol = 50 gallons
y = gallons of 100% water
z = gallons of 25% alcohol/water = 75% water/alcohol
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z = (x + y)
70x + 100y = 75z
70x + 100y = 75(x + y)
70*50 + 100y = 75(50 + y)
3500 + 100y = 3750 + 75y
25y = 250
y = 250/25
y = 10
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answer:
y = gallons of 100% water = 10
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