SOLUTION: The perimeter of rectangular room is 32 m. The length of the diagonal is 8 m more than the width. Find the dimension of the room.

Question 919246: The perimeter of rectangular room is 32 m. The length of the diagonal is 8 m more than the width. Find the dimension of the room.

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
w for width, L for length; and d for diagonal.
2w+2L=32 and d=8+w.

The diagonal serves as hypotenuse and w and L serve as legs of a right-triangle.
w^2+L^2=d^2.

Simplify the perimeter equation and substitute for d into the other two equations:
;
Still needs a bit of simplification, and then just solve the system.

;
Substitute...

, which are actually the two dimensions.
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