SOLUTION: how exactly do i get orderded pairs for the eguation it was an equation y=-x2+3x+3 then i the farthest i gotten on my formula is -3+- the square root of 21 divided by -2

Question 87904: how exactly do i get orderded pairs for the eguation it was an equation y=-x2+3x+3 then i the farthest i gotten on my formula is -3+- the square root of 21 divided by -2
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:
Starting with the general quadratic

the general form of the quadratic equation is:

So lets solve (notice , , and )

Plug in a=-1, b=3, and c=3

Square 3 to get 9

Multiply to get

Combine like terms in the radicand (everything under the square root)

Simplify the square root

Multiply 2 and -1 to get -2

So now the expression breaks down into two parts

or

Which approximate to

or

So our solutions are:
or

Notice when we graph we get:

when we use the root finder feature on a calculator, we find that and .So this verifies our answer
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how exactly do i get ordered pairs for the eguation
it was an equation y=-x^2+3x+3 then i the farthest i gotten on my formula is -3+- the square root of 21 divided by -2
--------------
It looks like you were trying to apply the quadratic formula. But
that is not the easiest way to find ordered pairs.
-----------
Getting ordered Pairs:
1st: pick a value for "x".
2nd: substitute that value of x into the equation to find the corresponding
value for y.
----------
For example:
If x=0, y= -0^2+4*0+3 = 3, giving you the ordered pair (0,3)
If x=1, y= -1^2+4*1+3 = 6, giving you the ordered pair (1,6)
etc.
=========
Cheers,
Stan H.
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