SOLUTION: The base of a triangle is 2cm more than the height. The base is increased by 4cm while the height is the same. The new area is 56cm. Whats the original area?

Question 848321: The base of a triangle is 2cm more than the height. The base is increased by 4cm while the height is the same. The new area is 56cm. Whats the original area?

Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
b = h + 2
b-2 = h
After change, our base is b+4
A = (1/2) * b * h
56 = (1/2)*(b+4)*(b-2)
56 = (1/2)(b^2+2b-8)
112 = b^2 +2b - 8
b^2 +2b -120 = 0
(b-10)(b+12) = 0
b = 10 [ignore b= -12]
This means h = 8
original area = 1/2 *(10)*(8) = cm^2
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