SOLUTION: Hi. My name is Allen and I can't figure out this problem. I solved for the hypotenuse but I don't know what to do after ...or if I was even supposed to find the hypotenuse. Please

Question 706089: Hi. My name is Allen and I can't figure out this problem. I solved for the hypotenuse but I don't know what to do after ...or if I was even supposed to find the hypotenuse. Please show me how to solve this problem. Thank you!
Two cars leave the origin; one goes north at 65 mph and the other goes south at 60 mph. After how many hours will they be 200 miles apart?
__________ hours
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Allen, the situation is simpler than needing a hypotenuse. North and South are opposite directions. The cars travel makes no triangle. You simply have the northbound driver having gone 65*h miles and the southbound driver having gone in the opposite direction for 60*h miles; When they are 200 miles apart, we have
65h+60h=200
h=8/5
h=1 hour and 36 minutes.
RELATED QUESTIONS
my question: y is less than or equal to -x-2 . i am trying to figure out what y and x... (answered by josmiceli,josgarithmetic)

Hi, earlier I posted my math problem but I couldn�t figure out how to upload the image so (answered by greenestamps)

Hi, I'm Allen and I asked for assistance with this problem earlier but got no response (I (answered by MathLover1)

Hi there, I am just stuck on a basic rule I have forgotten. I was given this problem:... (answered by jim_thompson5910)

Please can you help me with this equation, I have tried but can't figure it out. The... (answered by fners)

Hi, Please help me solve: S(t)=200[1-(0.86)^t] I've used the 10 hours for time to start (answered by edjones)

Hi, my name is Allen and I need assistance with this problem. I have no clue what to do.... (answered by nerdybill)

I can list all of the properties I need for this big test, but I don't know how to apply... (answered by ikleyn,math_tutor2020)

There is a question on the practice Compass test I don't understand. It is; For all... (answered by MathLover1)