SOLUTION: The coach purchased b balls for d dollars. If each ball had cost $2 more, how many balls could the coach have purchased for $200?

Question 67231This question is from textbook Advanced mathematics
: The coach purchased b balls for d dollars. If each ball had cost $2 more, how many balls could the coach have purchased for $200? This question is from textbook Advanced mathematics

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The coach purchased b balls for d dollars. If each ball had cost $2 more, how many balls could the coach have purchased for $200?
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The original purchase cost d/b dollars per ball
If each cost $2 more they each cost d/b+2
How many could be bought at this price for $200?
Ans: 200/[d/b + 2]
=200/[(d+2b)/2]
=400/[d+2b] is the number of balls that can be bought at the new price.
Cheers,
Stan H.
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