SOLUTION: If x^2 +y^2 = 40 and xy = 16, compare: A.) (x - y)^2 B.)12
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Question 67003This question is from textbook Advanced mathematics
: If x^2 +y^2 = 40 and xy = 16, compare: A.) (x - y)^2 B.)12
This question is from textbook Advanced mathematics
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
If x^2 +y^2 = 40 and xy = 16, compare: A.) (x - y)^2 B.)12
YOU WANT X-Y?
(X-Y)^2=X^2+Y^2-2XY=40-2*16=8
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