SOLUTION: Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form.
please help!!!!
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-> SOLUTION: Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form.
please help!!!!
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Question 66997This question is from textbook Advanced mathematics
: Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form.
please help!!!! This question is from textbook Advanced mathematics
You can put this solution on YOUR website! Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form.
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The mid-pt is ((-1/2),(1/2))
If every point of the desired line is equidistant from
from the given points it is perpendicular to the line
through the given points.
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Need to find the slope between the given points:
slope = [3--2]/[-3-2]=5/-5=-1
Therefore the slope of the desired line is +1.
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Find the equation of the line with slope=1 and passing thru ((-1/2),(1/2))
y-1/2=1(x--!/2)
y=x+(1/2)+(1/2)
y=x+1 is the equation of the line all of whose points
are equidistant from the given points.
By the way, I have never heard of the "general" form of a line.
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Cheers,
Stan H.
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