SOLUTION: Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form. please help!!!!

Question 66997This question is from textbook Advanced mathematics
: Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form.
please help!!!! This question is from textbook Advanced mathematics

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of the line that is equidistant from the points (-3,-2) and (2,3). Write your equation in general form.
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The mid-pt is ((-1/2),(1/2))
If every point of the desired line is equidistant from
from the given points it is perpendicular to the line
through the given points.
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Need to find the slope between the given points:
slope = [3--2]/[-3-2]=5/-5=-1
Therefore the slope of the desired line is +1.
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Find the equation of the line with slope=1 and passing thru ((-1/2),(1/2))
y-1/2=1(x--!/2)
y=x+(1/2)+(1/2)
y=x+1 is the equation of the line all of whose points
are equidistant from the given points.
By the way, I have never heard of the "general" form of a line.
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Cheers,
Stan H.

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