SOLUTION: Write an equation in slope-intercept form of the line through points S(3,-4) and T(8,3) m=y1-y2/x1-x2=-4-3/3-8=-7/-5=7/5 y-(-4)=7/5(x-3) y+4=7/5(x+3) This is as far as I could

Question 668627: Write an equation in slope-intercept form of the line through points S(3,-4) and T(8,3)
m=y1-y2/x1-x2=-4-3/3-8=-7/-5=7/5
y-(-4)=7/5(x-3)
y+4=7/5(x+3)
This is as far as I could go. Please help
Found 2 solutions by ReadingBoosters, stanbon:
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
Slope =
...
Using the determined slope and one of the coordinates,
-4 = + b
b = -4 -
b =
...
linear equation

...
Confirm using the other coordinate
3 = + b
b = 3 -
b =
...

.....................
Delighted to help.
-Reading Boosters
Wanting for others what we want for ourselves.
www.MyHomeworkAnswers.com

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write an equation in slope-intercept form of the line through points S(3,-4) and T(8,3)
m=(-4-3)/(3-8) = (-7/-5) = (7/5)
y-(-4)=7/5(x-3)
y+4=7/5(x+3)
------
y = (7/5)x + (21/5) - (20/5)
----
y = (7/5)x + (1/5)
=========================
An easier way to find the equation:
m=(-4-3)/(3-8) = (-7/-5) = (7/5)
Form: y = mx + b
You are told y = -4 when x = 3, and m = (7/5)
Solve for "b":
-4 = (7/5)(-3) + b
----
-20/5 = (-21/5) + b
-----
b = 1/5
----------
Ans: y = (7/5)x + (1/5)
============================
Cheers,
Stan H.
==============

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