# SOLUTION: solve for x: log2^(x+4) - log2^(x-4) = log2^5

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 Question 66573This question is from textbook Advanced mathematics : solve for x: log2^(x+4) - log2^(x-4) = log2^5This question is from textbook Advanced mathematics Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!solve for x: log2^(x+4) - log2^(x-4) = log2^5 DO YOU MEAN ALL LOGS ARE TO BASE 2? ASSUMING SO,SINCE ALL LOGS ARE TO SAME BASE , WE CAN DROP WRITING THE BASE AS UNDERSTOOD LOG(X+4)-LOG(X-4)=LOG(5) LOG[(X+4)/(X-4)]=LOG(5) (X+4)/(X-4)=5 X+4=5(X-4)=5X-20 20+4=5X-X=4X 4X=24 X=24/4=6 IF YOU REALLY MEANT POWERS THEN (X+4)LOG(2)-(X-4)LOG(2)=5LOG(2)..DIVIDING WITH LOG (2) X+4-(X-4)=5 X+4-X+4=5 8=5.IMPOSSIBLE