SOLUTION: solve for x:
log2^(x+4) - log2^(x-4) = log2^5
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Question 66573This question is from textbook Advanced mathematics
: solve for x:
log2^(x+4) - log2^(x-4) = log2^5
This question is from textbook Advanced mathematics
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
solve for x:
log2^(x+4) - log2^(x-4) = log2^5
DO YOU MEAN ALL LOGS ARE TO BASE 2? ASSUMING SO,SINCE ALL LOGS ARE TO SAME BASE , WE CAN DROP WRITING THE BASE AS UNDERSTOOD
LOG(X+4)-LOG(X-4)=LOG(5)
LOG[(X+4)/(X-4)]=LOG(5)
(X+4)/(X-4)=5
X+4=5(X-4)=5X-20
20+4=5X-X=4X
4X=24
X=24/4=6
IF YOU REALLY MEANT POWERS THEN
(X+4)LOG(2)-(X-4)LOG(2)=5LOG(2)..DIVIDING WITH LOG (2)
X+4-(X-4)=5
X+4-X+4=5
8=5.IMPOSSIBLE
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