SOLUTION: log4^2 + log4^8 = log4^(x+3)

Question 66495This question is from textbook Advanced mathematics
: log4^2 + log4^8 = log4^(x+3) This question is from textbook Advanced mathematics

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
log4^2 + log4^8 = log4^(x+3)
:
When you have logs of the same number you can just add the exponents,
you can write it:
log 4^(2+8)) = log 4^(x+3)
log 4^10 = log 4^(x+3)
:
from this we can see that:
10 = x+3
x = 7
:
Check it by substitution:
log 4^2 + log 4^8 = log 4^(7+3)
log 4^2 + log 4^8 = log 4^10
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