SOLUTION: If there were 600 people at a play, the total receipts were 9,800 pesos, and the admission price was 20 pesos for adults and 10 pesos for children, how many adults and how many chi

Question 445889: If there were 600 people at a play, the total receipts were 9,800 pesos, and the admission price was 20 pesos for adults and 10 pesos for children, how many adults and how many children were in attendance? .....thank you
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Adult x Numbers
Child ------------ y Numbers
x+y=600 .............1
20x+10y=9800 .............2
Eliminate y
multiply (1)by -10
Multiply (2) by 1
-10x-10y=-6000
20x+10y=9800
Add the two equations
10x= 3800
/10
x=380
plug value of x in (1)
x+y=600
380+y=600
y=600 -380
y=220

RELATED QUESTIONS
There were 480 people at a play. The admission price was $2 for adults and $1 for... (answered by Alan3354)

There were 600 people at a play. The admission price was $3.00 for adults and $1.00 for (answered by Nate)

there were 620 people at a play. The admission was $2 for adults and $1 for children. The (answered by josgarithmetic)

There were 590 people at play. the admission price was $3.00 for adults and $1.00 for... (answered by Jstrasner)

There were 360 people at a play. The admission price was $2 for adults and $1 for... (answered by ewatrrr)

the gate receipts at the basketball game in gym is 43,500 pesos for 2 500 spectators. If... (answered by Maths68)

Solve the problem. There were 420 people at a play. The admission price was $2 for adults (answered by lynnlo)

There were 430 people at a play. The admission price was $3 for adults and $1 for... (answered by stanbon)

There were 510 people at a play. The admission price was 2 for adults and 1 for children. (answered by Maths68)