SOLUTION: find the equation of the line that is equidistant from the points (-4, -3) and (4,6). Write the equation in slope-intercept form.

Question 416991: find the equation of the line that is equidistant from the points (-4, -3) and (4,6). Write the equation in slope-intercept form.
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Solution; First find the equation of line who pases on this two points;
(y+3)/6+3=(x+4)/4+4; (y+3)/6=(x+4)/8; 4(y+3)=3(x+4); 3x-4y=0; y=3x/4.
The midpoint is;x=(-4+4)/2=0; y=(-3+6)/2=1.5 ; (0,1.5) The equation of the line equidistant is; y-1.5=-4/3(x-0); y=-4x/3+1.5 or 8x+6y-9=0.
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