SOLUTION: I need help with this problem please.
A has coordinates (x1,x2) B (x2,y2) M (x1+x2/2 , y1+y2/2)
use the distance formula to show that AM= 1/2 AB
I tried to solve it but I g
Algebra.Com
Question 388356: I need help with this problem please.
A has coordinates (x1,x2) B (x2,y2) M (x1+x2/2 , y1+y2/2)
use the distance formula to show that AM= 1/2 AB
I tried to solve it but I got sqrt5 for both AM and AB
Please show me how to do it step by step.
Thank you!
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
A has coordinates (x1,y1) B (x2,y2) M (x1+x2/2 , y1+y2/2)
use the distance formula to show that AM= 1/2 AB
A (x1,x2) B (x2,y2)
M (x1+x2/2 , y1+y2/2)
...
AM = sqrt (x1-(x1+x2)/2)^2+(y1-(y1+y2)/2)^2)
AM = sqrt((x1-x2)^2+(y1-y2)^2
...
AB=
...
AM =
..
AM = 1/2*
...
substitute sqrt((x1-x2)^2+(y1-y2)^2) with AB
AM=1/2*AB
...
m.ananth@hotmail.ca
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