SOLUTION: What is the eighth term of the geometric sequence whose first three terms are
3, 6, and 12 Thanks
Algebra.Com
Question 333344: What is the eighth term of the geometric sequence whose first three terms are
3, 6, and 12 Thanks
Answer by Tutorteddy.Com(12) (Show Source): You can put this solution on YOUR website!
nth term Tn = ar^(n-1), where a is first term, Tn is nth term and r is the common ratio.
Here, r = 6/3 = 2.
Hence, 8th term = 3 X 2^(8 - 1) = 3 X 2^7 = 3 X 128 = 384
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