SOLUTION: Please help me to solve this problem: find the missing lengths of the triangle: 2x+1(hypotenuse), 2x-1, x .I know that the pythagorean theorem is a^2+b^2=c^2 I keep getting x=0, bu

Question 305983: Please help me to solve this problem: find the missing lengths of the triangle: 2x+1(hypotenuse), 2x-1, x .I know that the pythagorean theorem is a^2+b^2=c^2 I keep getting x=0, but I know it's not the right answer.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X^2+(2X-1)^2=(2X+1)^2
X^2+4X^2-4X+1=4X^2+4X+1
X^2+4X^2-4X^2-4X-4X+1-1=0
X^2-8X=0
X(X-8)=0
X=0
X-8=0
X=8 ANS.
8^2+(2*8-1)^2=(2*8+1)^2
64+(16-1)^2=(16+1)^2
64+15^2=17^2
64+225=289
289=289
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