# SOLUTION: half of a 16 in diameter circle fits snugly inside a rectangular box, how many square inches larger is the area of the box than the area of the circle?

Algebra ->  Algebra  -> Formulas -> SOLUTION: half of a 16 in diameter circle fits snugly inside a rectangular box, how many square inches larger is the area of the box than the area of the circle?      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Geometric and Other Formulas Answers archive In Depth

 Question 217361: half of a 16 in diameter circle fits snugly inside a rectangular box, how many square inches larger is the area of the box than the area of the circle?Answer by nerdybill(6948)   (Show Source): You can put this solution on YOUR website!half of a 16 in diameter circle fits snugly inside a rectangular box, how many square inches larger is the area of the box than the area of the circle? . Draw a diagram of the problem -- label everything you know -- it'll help you see the solution. . Area of "half circle" (1/2)(pi)8^2 = (1/2)(pi)8^2 = 32(pi) = 100.53 sq inches . box: length is 16 width is 8 Area = width*length Area = 8*16 Area = 128 sq inches . It is larger by: 128 - 100.53 = 27.47 sq inches