SOLUTION: M, J and A are points on a line where M and J are 10 cm apart and J and A are 18 cm apart. In how many ways can the three points be arranged on the line?Illustrate your answer.
Algebra.Com
Question 200378: M, J and A are points on a line where M and J are 10 cm apart and J and A are 18 cm apart. In how many ways can the three points be arranged on the line?Illustrate your answer.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
GIVEN : Straight Line, MJ =10,,, JA = 18
.
Looking at all combinations, define those possible
.
A-18-J-10-M
.
A-8-M-10-J
.
J-18-A-? -M,,,,not possible MJ=10
.
J-10-M-8_A
.
M-?-A-18-J,,,,,,not possible, MJ=10
.
M-10-J-18-A
RELATED QUESTIONS
J, M, and T are events such that T⊂J⊂M and Pr(J)=2132 , Pr(M)=2332, and... (answered by ikleyn)
Points T and J are 7 units apart. What is the number of points 2 units from T and 4 units (answered by Alan3354)
Points J, M, and B are collinear. How many lines do they determine? How many planes do... (answered by ikleyn)
How do i draw four points J, K, L, and M, no three of which are... (answered by richard1234)
Conditional proof
M->(K->L)
(L\/N) -> J
Therefore, M-> (K->J)
That's supposed to be (answered by math_helper)
there are 10 alphabets a, b, c, d, e, f, g, h, i, j. How many arrangements are there... (answered by sudhanshu_kmr)
in a triangle JKL,m (answered by Alan3354)
if angle H and angle J are supplementary and angle H is twice the measure of angle J... (answered by Fombitz)
J and K are independent events. P(J | K) = 0.68. Find P(J)
P(J) =
(answered by jim_thompson5910)