# SOLUTION: a farmer has 500 feet of fencing with which to build a rectangluar live stock pen and wants to enclose the maximum area. okay here is my prob i know how to get the maximum area but

Algebra ->  Algebra  -> Formulas -> SOLUTION: a farmer has 500 feet of fencing with which to build a rectangluar live stock pen and wants to enclose the maximum area. okay here is my prob i know how to get the maximum area but      Log On

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 Click here to see ALL problems on Geometric formulas Question 186475: a farmer has 500 feet of fencing with which to build a rectangluar live stock pen and wants to enclose the maximum area. okay here is my prob i know how to get the maximum area but it also says to show a graph of the possibilties and i am stuck i did get help with and understand how to use varibles but i'm just not sure how i get this graphed is ther some fabulous trick i don't know about??i am struggling with this last math project and totally bombed on the last one i just need a few pointers on what to do thank you all so very much tanyaAnswer by rapaljer(4667)   (Show Source): You can put this solution on YOUR website!Let x = width of the pen. If you have 500 feet of fence, then this is the perimeter, so 2W + 2L = 500 You need to find the length L in terms of x, remembering that x= width. 2x + 2L = 500 You have to solve for L. Divide both sides by 2 to simplify things a bit: x + L = 250 Subtract x from each side L=250-x So, now you have a formula for Area in terms of x: A=W*L A= x*(250-x) Graph y=x*(250-x) To find the maximum area, you can graph this equation. I recommend that you graph this from x=0 to about x=250. It can't go past these values for x, right? Now, (did you say that you know what the maximum is? It's a square, so each side will be 500/4 = 125, and the area will be 125^2 = 15625!!) graph y values from y=0 up to about 16000. The graph in this window should look like this: This confirms that the maximum occurs at x = 125, and the value there for the area is y = about 15,000 or 16,000. The exact value can be found by substituting x = 125 into the formula A = x(250-x). R^2