SOLUTION: In a triangle of perimeter 72 in., the length of the first side is twice the length of the second side, and the length of the third side is 8 in. more than the length of the second

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Question 1194217: In a triangle of perimeter 72 in., the length of the first side is twice the length of the second side, and the length of the third side is 8 in. more than the length of the second side. Find the lengths of the three sides in inches.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

Let the second side length be x;  then first side length is 2x and third side length is (x+8).


From the problem, you have this equation

    x + 2x + (x+8) = 72.


Its solution is  x= 16 cm.


So, first side length is 32 cm; second side length is 16 cm and third side length is 24 cm.


The triangle inequalities are satisfied, so the obtained numbers provide the ANSWER.

Solved.



Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
Firstside            2d
Secondside            d
Thirdside             d+8
PERIMETER             72

Simple accounting. Be sure to check if the result satisfied Triangle Inequality Theorem.
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