SOLUTION: Given: rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E DB = AB = 6 Find: AC in simplest radical form and approximation

Question 1193778: Given: rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E
DB = AB = 6 Find: AC in simplest radical form and approximation
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
DB=AB=6
so all sides are 6.
EB=3, AB=6. AEB is a 30-60-90 right triangle with the diagonal the longer of the two lengths at 3 sqrt(3).
So the length of the diagonal is double that or 6 sqrt (3).
Because EB is 1/2 of AB in a right triangle, this is a 30-60-90 rt triangle.
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