SOLUTION: Rectangle ABCD is given Given: AB = x + y BC = x + 2y CD = 2x − y − 2 DA = 3x − 3y + 3 Find:x and y

Question 1193117: Rectangle ABCD is given
Given:
AB = x + y
BC = x + 2y
CD = 2x − y − 2
DA = 3x − 3y + 3
Find:x and y
Found 2 solutions by greenestamps, MathLover1:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Opposite sides AB and CD are congruent; as are opposite sides BC and DA. Using the given information,

Put each equation n Ax+By=C form....

My preference would be to solve using elimination. Multiply the first equation by -2 and add the two equations to eliminate x.

Substitute y=7 in any earlier equation to solve for x. I leave that little bit to you.

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

Rectangle is given
Given:

Find: and

recall that opposite sides of a rectangle are equal in length, so
and
then we have
........solve for

.........eq.1

......solve for

......multiply by
.......solve for

go to
.........eq.1, substitute

now we can find the sides length:

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