SOLUTION: ▱ABCD m∠A = (2x + 4)° and m∠B = (3x − 34)°. i found x which i got 42. Find the measure of each angle (in degrees) of ▱ABCD. m∠A = ° m∠B = ° m∠C = °

Question 1193079: ▱ABCD
m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
i found x which i got 42.
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
°
Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
I guess you have a parallelogram. If so than and

given:
<°
and
< °.

then
< - <

then
<°=><°
< °=>< °

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

You have solved correctly for x.

Angles A and B are supplementary, so

(2x+4)+(3x-34)=180
5x-30=180
5x=210
x=42

Now plug in x=42 to find the measure of angle A (2x+4) and angle B (3x-34).

Then, since this is a parallelogram, the measure of angle C is the same as angle A, and the measure of angle D is the same as angle B.

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