SOLUTION: For a quadrilateral ABCD, the measures of its angles are given below. m∠A = (x + 14)° m∠B = (2(x + 2))° m∠C = 3/2 x − 13 ° m∠D = 7/3 x − 14 °Find x. then

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Question 1193037: For a quadrilateral ABCD, the measures of its angles are given below.
m∠A = (x + 14)°
m∠B = (2(x + 2))°
m∠C =
3/2
x − 13
°
m∠D =
7/3
x − 14
°Find x.
then, Find the measure of each angle (in degrees) of ABCD.
I'm not sure where to even start here. here's what I got so far: x+14+2x+4=360..and x+10+2x=360...so x+10=360..and i got 36
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
For a quadrilateral ABCD, the measures of its angles are given below.
°
°=°
°
°
Find .

.......both sides multiply by






then, measures of angles are:
°
°
°
°

also, since you have a quadrilateral you know that opposite angles are equal

then you can find the value of this way:
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

For a quadrilateral ABCD, the measures of its angles are given below.
m∠A = (x + 14)°
m∠B = (2(x + 2))°
m∠C =
3/2
x − 13
°
m∠D =
7/3
x − 14
°Find x.
then, Find the measure of each angle (in degrees) of ABCD.
I'm not sure where to even start here. here's what I got so far: x+14+2x+4=360..and x+10+2x=360...so x+10=360..and i got 36
The answer depends on whether the given angles are:  

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