SOLUTION: In triangle JKL, an angle bisector drawn from vertex K intersects the opposite side at point P. If < JKL is 2y + 25 and < PKL is 8y - 17, what is the measure of < JKL
Question 1151992: In triangle JKL, an angle bisector drawn from vertex K intersects the opposite side at point P. If < JKL is 2y + 25 and < PKL is 8y - 17, what is the measure of < JKL Found 2 solutions by ikleyn, MathLover1:Answer by ikleyn(52793) (Show Source): You can put this solution on YOUR website! .
From the condition,
2y + 25 = 2*(8y - 17).
Simplify and solve for y
2y + 25 = 16y - 34
25 + 34 = 16y - 2y
59 = 14y
y = .
The measure of < JKL is 2y+25 = = + 25 = 8 + + 25 = . ANSWER