SOLUTION: If 0 < A < 90 degrees, prove geometrically that cos(A-90°) = sinA

Question 1151437: If 0 < A < 90 degrees, prove geometrically that cos(A-90°) = sinA
Answer by ikleyn(52794) (Show Source): You can put this solution on YOUR website!
.


For it, draw the unit circle in a coordinate plane, mark the angle A in it and then use definitions of sine and cosine.

RELATED QUESTIONS
If 0 (answered by Edwin McCravy)
If 0 (answered by josgarithmetic)
If 0 (answered by josgarithmetic)
If 0 degrees < A, B < 90 degrees, and sinA=cosB, compute... (answered by ikleyn)
If cos(A-B)+cos(B-C)+cos(C-A)= -3/2, prove that:... (answered by robertb)
find the value of sin(a-b) if cos a = 15/17, cot = 24/7, 0 degrees (answered by stanbon)
if A+B=90;SinA=3/4 then... (answered by Edwin McCravy)
Find values of sin(a-b)if cos a=15/17, cot b=24/7, 0 degrees (answered by lwsshak3)
If {{{ 0 <= x <= 90}}}�, prove that {{{ 1 <= sin(x) + cos(x) <= sqrt(2)... (answered by htmentor)