SOLUTION: For the transformation T, write the inverse T-1. T: (x, y) --> ( 2x, y + 5) T-1: (x, y)--> A.) (x - 2, y - 5) B.) (�x, y - 5) C.) (2x

SOLUTION: For the transformation T, write the inverse T-1. T: (x, y) --> ( 2x, y + 5) T-1: (x, y)--> A.) (x - 2, y - 5) B.) (�x, y - 5) C.) (2x - 1, y + 4)

Question 1091733: For the transformation T, write the inverse T^-1.
T: (x, y) --> ( 2x, y + 5)
T^-1: (x, y)-->
A.) (x - 2, y - 5)
B.) (�x, y - 5)
C.) (2x - 1, y + 4)
Please explain. Thank you.
Found 2 solutions by Fombitz, Edwin McCravy:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
T takes the x value and doubles it and adds 5 to the y value.
So T's inverse, would take half of the x value and subtract 5 from the y value.

Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
For the transformation T, write the inverse T^-1.
T: (x, y) --> (2x, y + 5)
T^-1 (x, y)-->
A.) (x - 2, y - 5)
B.) (�x, y - 5)
C.) (2x - 1, y + 4)

The inverse of T, written T^-1, does the exact opposite to the coordinates as T does to them. Transform T changes x to 2x, which is to double the first coordinate. The opposite of doubling the first coordinate is halving the first coordinate, so T^-1 takes x to �x Transform T also takes y to y+5, which is adding 5 to the second coordinate. The opposite of adding 5 to the second coordinate is subtracting 5 from the second coordinate, so T^-1 takes y to y-5. Therefore, T^-1: (x, y)--> (�x, y-5) Correct answer is B. Edwin

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SOLUTION: For the transformation T, write the inverse T<sup>-1</sup>. T: (x, y) --> ( 2x, y + 5) T<sup>-1</sup>: (x, y)--> A.) (x - 2, y - 5) B.) (�x, y - 5) C.) (2x - 1, y + 4)