SOLUTION: The four term of a G.p is 56 while the six term is 7/8.Find the G.p and hence sum to infinity

Algebra.Com
Question 1049605: The four term of a G.p is 56 while the six term is 7/8.Find the G.p and hence sum to infinity

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
The four term of a G.p is 56 while the six term is 7/8.Find the G.p and hence sum to infinity
---
g(4) = a*r^3 = 56
g(6) = a*r^5 = 7/8
--------
Divide g(6) by g(4) to get r^2 = (7/8)/56 = 1/(8^2)
r = 1/8
Solve for "a"::
a*r^3 = 56
a = 56/(1/8)^3 = 28672
------
Sum to infinity:: = a/(1-r) = 28673/(7/8) = 32768
------------
Cheers,
Stan H.
-------------------

RELATED QUESTIONS

The fourth term of a GP (Geometric Progression) is 56 while the sixth term is 7/8. Find... (answered by stanbon)
A G.P has the second term as 9 and the fourth term is as 81.find the some of the first... (answered by greenestamps)
The sum of the first and 4th term of a G.P is -1575 while the sum of the 3rd and 6th term (answered by greenestamps)
A G. P is such that the third term is nine times the first term, while the second term (answered by greenestamps)
The third term of a g.p is 12 and the first term is 48.find the sum of the first 11... (answered by mananth,ikleyn)
the sum of the 1st and 2nd term of a geometric progression is 10 while its sum to... (answered by galactus)
Given that the 2rd term of a G.p is 180 and the 3rd term is 360, calculate: a) the first (answered by josgarithmetic,math_tutor2020)
the 8th term of a G.P is 640.if the first term is 5,find the common ratio and the 10th... (answered by ikleyn)
The nth term of a G.P. is 2x3^n for all n. Find (a) the first term (b) the common ratio... (answered by mananth)