SOLUTION: A lot runs between two parallel streets. The length of the lot on one of the streets is 80-ft. The length of the lot on the other street is 100-ft. The area of the lot is 18,000
Algebra.Com
Question 1037271: A lot runs between two parallel streets. The length of the lot on one of the streets is 80-ft. The length of the lot on the other street is 100-ft. The area of the lot is 18,000 square feet. How far apart are the two streets? (The formula for the area of a trapezoid is A=1/2(b1+b2)h
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Area = 1/2(b1 + b2)x h
Area = 18,000 ft^2
b1 = 80 ft
b2 = 100 ft
18,000 = 1/2(80 + 100) x h
36,000 = (180)h
h = 36,000/180
h = 200ft.
This is the distance between streets.
Hope this helps :-)
RELATED QUESTIONS
A lot runs between two parallel streets. The length of the lot on one of the streets is... (answered by math_tutor2020)
A triangular city lot bounded by 3 streets has a length of 300 fetter on one street, 250... (answered by stanbon,addingup)
your house is on the corner lot at the intersection of two streets meeting at a right... (answered by fcabanski)
Two streets meet at an angle of 52 degrees. If a triangular lot has frontages of 60 m and (answered by Theo)
Two streets meet at an angle of 52o. If a triangular lot has frontages of 60 m and 65 m... (answered by Paul)
Harold Johnson lives on a four-sided, 50,000-square-foot lot that is bounded on two sides (answered by math_tutor2020)
Alright, I've got one last question. I keep getting half of what the book says the... (answered by Fombitz)
Can you please help me on this problem. I dont get it.
A corner lot that originally... (answered by Fombitz)
A corner lot that originally was square lost 185 m squared of area when one of the... (answered by ankor@dixie-net.com)