SOLUTION: xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2

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Question 1011843: xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2
Found 4 solutions by addingup, ikleyn, MathTherapy, Fombitz:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
(x^2+y^2)=25 take the square root on both sides:
x+y= 5
(x+y)2^2 and since x+y= 5:
5(2)^2= 5(4)= 20
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2 ?
------------------------------------------------------- 
xy=12,  =  implies that

 =  +  = 25 + 2*12 = 25 + 24 = 49.

Again:

 =  = 49.

So, if you need , you just have it: it is 49.

What you do REALLY need, I don't know, because you do neglect to use parentheses properly.

If it is , then it is equal to 4*49.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2
   ;   



Observing , it's obvious that x and y MUST be 3 and 4

Likewise x and y MUST be 3 and 4 as xy = 12



Proving this, we get:

 --------> , which becomes: 25 + 2(12) = 25 + 24 = 49

Since , then x + y = 7 ------ Square root of each side was taken



I don’t know what  means but you should be able to determine what’s needed since it was found that: 

 & , and the following were given:  &  

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
 



 

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