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Tutors Answer Your Questions about expressions (FREE)
Question 93260: hi there,
I asked the following question before and I had a solution given to me, I do not understand some of it though, some guidance would be great.
s=u.(v-u)/a + 1/2a((v-u)/a)^2
it should end up as v^2=u^2+2as
first step was to multiply by 2a giving....
2as=2u(v-u)+(v-u)^2
expanding
2as= 2uv-2u^2+v^2-2vu+u^2
apparently by collecting terms this is equal to 2as=v^2-u^2, could someone please explain this last step for me
Click here to see answer by bucky(1732)   |
Question 94342: AHi. I was wondering if I could recieve help on the following problem:
I know you do order of operations, but I do not know if it matters if I multiply or divide first after I get the exponent.
4 - 4^2 divided by 8 x 3 + 6
What I did was get 4 -16 divided by 8 x 3 + 6
Then if I multiplied first, I would get 4 - 16 divided by 24 + 6
Then I would get 4 - 2/3 + 6. Then I'd get 9 and 1/3.
On my calculator I got 4, but that would only work if I divided before I multiplied. I know division and multiplication are inverse opperations, so would it be okay if I divided first and got 4 as the answer?
Thanks.
Click here to see answer by stanbon(26297) |
Question 94342: AHi. I was wondering if I could recieve help on the following problem:
I know you do order of operations, but I do not know if it matters if I multiply or divide first after I get the exponent.
4 - 4^2 divided by 8 x 3 + 6
What I did was get 4 -16 divided by 8 x 3 + 6
Then if I multiplied first, I would get 4 - 16 divided by 24 + 6
Then I would get 4 - 2/3 + 6. Then I'd get 9 and 1/3.
On my calculator I got 4, but that would only work if I divided before I multiplied. I know division and multiplication are inverse opperations, so would it be okay if I divided first and got 4 as the answer?
Thanks.
Click here to see answer by edjones(3299)  |
Question 94340: ``Hi, I need help with the problem:
3+ (1 + 2^3)^2
I keep getting different answers. When I worked it I got 68, but when I used my calculator it said 84. When I worked it, I squared the 1 and got 1 and squared the 2^3 and got 2^6. Then I added 1 to the 64 (2^6) and got 65. Then I added 3 and got 68. I know how the caluclator got 84, but the way I learned it you are supposed to multiple by the 2 first. If you could help me that would be great.
Thanks
Click here to see answer by stanbon(26297) |
Question 94400: i have previously submitted this question but have not received an answer. I have had a go myself but am not sure if I have done it correctly. would you please be able to check what I have done, and let me know if I am on the right track? Thank you.
The problem is a substitution equation where a=2,b=3,c=-4 & d=-1.
=60
Click here to see answer by praseenakos@yahoo.com(417) |
Question 94400: i have previously submitted this question but have not received an answer. I have had a go myself but am not sure if I have done it correctly. would you please be able to check what I have done, and let me know if I am on the right track? Thank you.
The problem is a substitution equation where a=2,b=3,c=-4 & d=-1.
=60
Click here to see answer by jim_thompson5910(13794) |
Question 94478: If 4 is added to a certain number, the result divided by 2, that result multiplied by 5, and then 6 subtracted from that result, the answer is 29.
The question says: choose a variable and write an algebraic equation to reprssent the puzzle
Click here to see answer by tutorcecilia(2042) |
Question 95673: Hello, can you please help me? The directions say to simplify the xpression involving rational exponents. Assume all variables represent positive real numbers. Write the answer with positive exponents.
(x^2y^-3z)^1/2
______________
x^1/2yz^-1/2
Thank you for your help.
Click here to see answer by stanbon(26297) |
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